Base | Representation |
---|---|
bin | 10010101010000001… |
… | …001101000000100011 |
3 | 1220201002022212001201 |
4 | 102222001031000203 |
5 | 312011232430311 |
6 | 13111441542031 |
7 | 1306263560014 |
oct | 225201150043 |
9 | 56632285051 |
10 | 20032311331 |
11 | 854a798aaa |
12 | 3a70944917 |
13 | 1b732ab976 |
14 | d806d700b |
15 | 7c39ee9c1 |
hex | 4aa04d023 |
20032311331 has 4 divisors (see below), whose sum is σ = 20056652752. Its totient is φ = 20007969912.
The previous prime is 20032311323. The next prime is 20032311361. The reversal of 20032311331 is 13311323002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20032311331 - 23 = 20032311323 is a prime.
It is a super-2 number, since 2×200323113312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20032311299 and 20032311308.
It is not an unprimeable number, because it can be changed into a prime (20032311361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12169476 + ... + 12171121.
It is an arithmetic number, because the mean of its divisors is an integer number (5014163188).
Almost surely, 220032311331 is an apocalyptic number.
20032311331 is a deficient number, since it is larger than the sum of its proper divisors (24341421).
20032311331 is an equidigital number, since it uses as much as digits as its factorization.
20032311331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24341420.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 20032311331 its reverse (13311323002), we get a palindrome (33343634333).
The spelling of 20032311331 in words is "twenty billion, thirty-two million, three hundred eleven thousand, three hundred thirty-one".
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