200323130012132 has 6 divisors (see below), whose sum is σ = 350565477521238. Its totient is φ = 100161565006064.

The previous prime is 200323130012099. The next prime is 200323130012141. The reversal of 200323130012132 is 231210031323002.

It can be written as a sum of positive squares in only one way, i.e., 141401017958656 + 58922112053476 = 11891216^2 + 7676074^2 .

It is a super-4 number, since 4×200323130012132⁴ (a number of 58 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 200323130012098 and 200323130012107.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25040391251513 + ... + 25040391251520.

It is an arithmetic number, because the mean of its divisors is an integer number (58427579586873).

Almost surely, 2^{200323130012132} is an apocalyptic number.

It is an amenable number.

200323130012132 is a deficient number, since it is larger than the sum of its proper divisors (150242347509106).

200323130012132 is a wasteful number, since it uses less digits than its factorization.

200323130012132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50080782503037 (or 50080782503035 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 200323130012132 its reverse (231210031323002), we get a palindrome (431533161335134).

The spelling of 200323130012132 in words is "two hundred trillion, three hundred twenty-three billion, one hundred thirty million, twelve thousand, one hundred thirty-two".