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20032413 = 36677471
BaseRepresentation
bin100110001101…
…0101110011101
31101200202022020
41030122232131
520112014123
61553210353
7332162352
oct114325635
941622266
1020032413
1110342715
1268609b9
1341c50cb
142936629
151b5a7e3
hex131ab9d

20032413 has 4 divisors (see below), whose sum is σ = 26709888. Its totient is φ = 13354940.

The previous prime is 20032399. The next prime is 20032423. The reversal of 20032413 is 31423002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20032413 - 25 = 20032381 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20032392 and 20032401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20032423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3338733 + ... + 3338738.

It is an arithmetic number, because the mean of its divisors is an integer number (6677472).

Almost surely, 220032413 is an apocalyptic number.

It is an amenable number.

20032413 is a deficient number, since it is larger than the sum of its proper divisors (6677475).

20032413 is an equidigital number, since it uses as much as digits as its factorization.

20032413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6677474.

The product of its (nonzero) digits is 144, while the sum is 15.

The square root of 20032413 is about 4475.7583714942. The cubic root of 20032413 is about 271.5883198785.

Adding to 20032413 its reverse (31423002), we get a palindrome (51455415).

The spelling of 20032413 in words is "twenty million, thirty-two thousand, four hundred thirteen".

Divisors: 1 3 6677471 20032413