2003320100013 has 4 divisors (see below), whose sum is σ = 2671093466688. Its totient is φ = 1335546733340.

The previous prime is 2003320100011. The next prime is 2003320100039. The reversal of 2003320100013 is 3100010233002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2003320100013 - 2¹ = 2003320100011 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2003320099965 and 2003320100001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003320100011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333886683333 + ... + 333886683338.

It is an arithmetic number, because the mean of its divisors is an integer number (667773366672).

Almost surely, 2^{2003320100013} is an apocalyptic number.

It is an amenable number.

2003320100013 is a deficient number, since it is larger than the sum of its proper divisors (667773366675).

2003320100013 is an equidigital number, since it uses as much as digits as its factorization.

2003320100013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 667773366674.

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 2003320100013 its reverse (3100010233002), we get a palindrome (5103330333015).

The spelling of 2003320100013 in words is "two trillion, three billion, three hundred twenty million, one hundred thousand, thirteen".