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200332300121341 is a prime number
BaseRepresentation
bin101101100011001101111111…
…100101011111010011111101
3222021022120200102221020222221
4231203031333211133103331
5202224221022312340331
61550023215502205341
760124350102614143
oct5543157745372375
9867276612836887
10200332300121341
11589174a6847903
121a5758a9b83851
1387a2340b6b00b
1437681c6871593
15182618226e711
hexb6337f95f4fd

200332300121341 has 2 divisors, whose sum is σ = 200332300121342. Its totient is φ = 200332300121340.

The previous prime is 200332300121297. The next prime is 200332300121347. The reversal of 200332300121341 is 143121003233002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120803092174116 + 79529207947225 = 10991046^2 + 8917915^2 .

It is a cyclic number.

It is not a de Polignac number, because 200332300121341 - 223 = 200332291732733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200332300121347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100166150060670 + 100166150060671.

It is an arithmetic number, because the mean of its divisors is an integer number (100166150060671).

Almost surely, 2200332300121341 is an apocalyptic number.

It is an amenable number.

200332300121341 is a deficient number, since it is larger than the sum of its proper divisors (1).

200332300121341 is an equidigital number, since it uses as much as digits as its factorization.

200332300121341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 200332300121341 its reverse (143121003233002), we get a palindrome (343453303354343).

The spelling of 200332300121341 in words is "two hundred trillion, three hundred thirty-two billion, three hundred million, one hundred twenty-one thousand, three hundred forty-one".