Base | Representation |
---|---|
bin | 101101100011001101111111… |
… | …100101011111010011111101 |
3 | 222021022120200102221020222221 |
4 | 231203031333211133103331 |
5 | 202224221022312340331 |
6 | 1550023215502205341 |
7 | 60124350102614143 |
oct | 5543157745372375 |
9 | 867276612836887 |
10 | 200332300121341 |
11 | 589174a6847903 |
12 | 1a5758a9b83851 |
13 | 87a2340b6b00b |
14 | 37681c6871593 |
15 | 182618226e711 |
hex | b6337f95f4fd |
200332300121341 has 2 divisors, whose sum is σ = 200332300121342. Its totient is φ = 200332300121340.
The previous prime is 200332300121297. The next prime is 200332300121347. The reversal of 200332300121341 is 143121003233002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 120803092174116 + 79529207947225 = 10991046^2 + 8917915^2 .
It is a cyclic number.
It is not a de Polignac number, because 200332300121341 - 223 = 200332291732733 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200332300121347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100166150060670 + 100166150060671.
It is an arithmetic number, because the mean of its divisors is an integer number (100166150060671).
Almost surely, 2200332300121341 is an apocalyptic number.
It is an amenable number.
200332300121341 is a deficient number, since it is larger than the sum of its proper divisors (1).
200332300121341 is an equidigital number, since it uses as much as digits as its factorization.
200332300121341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 200332300121341 its reverse (143121003233002), we get a palindrome (343453303354343).
The spelling of 200332300121341 in words is "two hundred trillion, three hundred thirty-two billion, three hundred million, one hundred twenty-one thousand, three hundred forty-one".
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