Base | Representation |
---|---|
bin | 11101001001101111110… |
… | …110000110011101001011 |
3 | 21002111221121010000022012 |
4 | 131021233312012131023 |
5 | 230310310242310011 |
6 | 4132152340250135 |
7 | 264510262230503 |
oct | 35115766063513 |
9 | 7074847100265 |
10 | 2003331213131 |
11 | 702676274596 |
12 | 2843136a094b |
13 | 116bb47548c1 |
14 | 6cd67072a03 |
15 | 371a0698a8b |
hex | 1d26fd8674b |
2003331213131 has 2 divisors, whose sum is σ = 2003331213132. Its totient is φ = 2003331213130.
The previous prime is 2003331213083. The next prime is 2003331213259. The reversal of 2003331213131 is 1313121333002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2003331213131 - 214 = 2003331196747 is a prime.
It is a super-2 number, since 2×20033312131312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2003331213097 and 2003331213106.
It is not a weakly prime, because it can be changed into another prime (2003331213031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001665606565 + 1001665606566.
It is an arithmetic number, because the mean of its divisors is an integer number (1001665606566).
Almost surely, 22003331213131 is an apocalyptic number.
2003331213131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003331213131 is an equidigital number, since it uses as much as digits as its factorization.
2003331213131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 2003331213131 its reverse (1313121333002), we get a palindrome (3316452546133).
The spelling of 2003331213131 in words is "two trillion, three billion, three hundred thirty-one million, two hundred thirteen thousand, one hundred thirty-one".
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