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2003331213131 is a prime number
BaseRepresentation
bin11101001001101111110…
…110000110011101001011
321002111221121010000022012
4131021233312012131023
5230310310242310011
64132152340250135
7264510262230503
oct35115766063513
97074847100265
102003331213131
11702676274596
122843136a094b
13116bb47548c1
146cd67072a03
15371a0698a8b
hex1d26fd8674b

2003331213131 has 2 divisors, whose sum is σ = 2003331213132. Its totient is φ = 2003331213130.

The previous prime is 2003331213083. The next prime is 2003331213259. The reversal of 2003331213131 is 1313121333002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2003331213131 - 214 = 2003331196747 is a prime.

It is a super-2 number, since 2×20033312131312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2003331213097 and 2003331213106.

It is not a weakly prime, because it can be changed into another prime (2003331213031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001665606565 + 1001665606566.

It is an arithmetic number, because the mean of its divisors is an integer number (1001665606566).

Almost surely, 22003331213131 is an apocalyptic number.

2003331213131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003331213131 is an equidigital number, since it uses as much as digits as its factorization.

2003331213131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 2003331213131 its reverse (1313121333002), we get a palindrome (3316452546133).

The spelling of 2003331213131 in words is "two trillion, three billion, three hundred thirty-one million, two hundred thirteen thousand, one hundred thirty-one".