20033334500345 has 4 divisors (see below), whose sum is σ = 24040001400420. Its totient is φ = 16026667600272.

The previous prime is 20033334500329. The next prime is 20033334500369. The reversal of 20033334500345 is 54300543333002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5389181174521 + 14644153325824 = 2321461^2 + 3826768^2 .

It is a cyclic number.

It is not a de Polignac number, because 20033334500345 - 2⁴ = 20033334500329 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003333450030 + ... + 2003333450039.

It is an arithmetic number, because the mean of its divisors is an integer number (6010000350105).

Almost surely, 2^{20033334500345} is an apocalyptic number.

It is an amenable number.

20033334500345 is a deficient number, since it is larger than the sum of its proper divisors (4006666900075).

20033334500345 is an equidigital number, since it uses as much as digits as its factorization.

20033334500345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4006666900074.

The product of its (nonzero) digits is 194400, while the sum is 35.

Adding to 20033334500345 its reverse (54300543333002), we get a palindrome (74333877833347).

The spelling of 20033334500345 in words is "twenty trillion, thirty-three billion, three hundred thirty-four million, five hundred thousand, three hundred forty-five".