Base | Representation |
---|---|
bin | 1001000111000011001101… |
… | …10111111111111101110011 |
3 | 2121221011211210222112211221 |
4 | 10203201212313333331303 |
5 | 10111212003034040444 |
6 | 110335124053045511 |
7 | 4135240436314504 |
oct | 443414667777563 |
9 | 77834753875757 |
10 | 20033453424499 |
11 | 642415a206aa9 |
12 | 22b674b026897 |
13 | b241b9c88988 |
14 | 4d38a51bcbab |
15 | 24b1b1c6ba84 |
hex | 123866dfff73 |
20033453424499 has 2 divisors, whose sum is σ = 20033453424500. Its totient is φ = 20033453424498.
The previous prime is 20033453424497. The next prime is 20033453424527. The reversal of 20033453424499 is 99442435433002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20033453424499 - 21 = 20033453424497 is a prime.
It is a super-2 number, since 2×200334534244992 (a number of 27 digits) contains 22 as substring.
Together with 20033453424497, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (20033453424493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10016726712249 + 10016726712250.
It is an arithmetic number, because the mean of its divisors is an integer number (10016726712250).
Almost surely, 220033453424499 is an apocalyptic number.
20033453424499 is a deficient number, since it is larger than the sum of its proper divisors (1).
20033453424499 is an equidigital number, since it uses as much as digits as its factorization.
20033453424499 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11197440, while the sum is 52.
The spelling of 20033453424499 in words is "twenty trillion, thirty-three billion, four hundred fifty-three million, four hundred twenty-four thousand, four hundred ninety-nine".
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