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20033500336852 = 225008375084213
BaseRepresentation
bin1001000111000011010011…
…01010111101001011010100
32121221011222002020221111111
410203201221222331023110
510111212102041234402
6110335132450344404
74135241546132302
oct443415152751324
977834862227444
1020033500336852
116424183738a42
1222b676288b104
13b241c6902872
144d38ab511272
1524b1b5e369d7
hex123869abd2d4

20033500336852 has 6 divisors (see below), whose sum is σ = 35058625589498. Its totient is φ = 10016750168424.

The previous prime is 20033500336769. The next prime is 20033500336873. The reversal of 20033500336852 is 25863300533002.

It can be written as a sum of positive squares in only one way, i.e., 10706010176016 + 9327490160836 = 3272004^2 + 3054094^2 .

It is a super-3 number, since 3×200335003368523 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2504187542103 + ... + 2504187542110.

Almost surely, 220033500336852 is an apocalyptic number.

It is an amenable number.

20033500336852 is a deficient number, since it is larger than the sum of its proper divisors (15025125252646).

20033500336852 is a wasteful number, since it uses less digits than its factorization.

20033500336852 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5008375084217 (or 5008375084215 counting only the distinct ones).

The product of its (nonzero) digits is 388800, while the sum is 40.

Adding to 20033500336852 its reverse (25863300533002), we get a palindrome (45896800869854).

The spelling of 20033500336852 in words is "twenty trillion, thirty-three billion, five hundred million, three hundred thirty-six thousand, eight hundred fifty-two".

Divisors: 1 2 4 5008375084213 10016750168426 20033500336852