Base | Representation |
---|---|
bin | 11101001001110011111… |
… | …100000111001111011111 |
3 | 21002112010101100120100011 |
4 | 131021303330013033133 |
5 | 230310430333214304 |
6 | 4132203232344051 |
7 | 264512055106246 |
oct | 35116374071737 |
9 | 7075111316304 |
10 | 2003399898079 |
11 | 702701017608 |
12 | 2843326a5027 |
13 | 116bc5a52998 |
14 | 6cd7223195d |
15 | 371a6714c04 |
hex | 1d273f073df |
2003399898079 has 2 divisors, whose sum is σ = 2003399898080. Its totient is φ = 2003399898078.
The previous prime is 2003399898023. The next prime is 2003399898091. The reversal of 2003399898079 is 9708989933002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2003399898079 - 217 = 2003399767007 is a prime.
It is a super-2 number, since 2×20033998980792 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003399898679) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001699949039 + 1001699949040.
It is an arithmetic number, because the mean of its divisors is an integer number (1001699949040).
Almost surely, 22003399898079 is an apocalyptic number.
2003399898079 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003399898079 is an equidigital number, since it uses as much as digits as its factorization.
2003399898079 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52907904, while the sum is 67.
The spelling of 2003399898079 in words is "two trillion, three billion, three hundred ninety-nine million, eight hundred ninety-eight thousand, seventy-nine".
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