Base | Representation |
---|---|
bin | 10010101010001000… |
… | …000100001010011111 |
3 | 1220201012201020112012 |
4 | 102222020010022133 |
5 | 312012213010421 |
6 | 13111544301435 |
7 | 1306315061201 |
oct | 225210041237 |
9 | 56635636465 |
10 | 20034110111 |
11 | 85508074a4 |
12 | 3a7147187b |
13 | 1b7378b632 |
14 | d80a44771 |
15 | 7c3c5795b |
hex | 4aa20429f |
20034110111 has 2 divisors, whose sum is σ = 20034110112. Its totient is φ = 20034110110.
The previous prime is 20034110101. The next prime is 20034110147. The reversal of 20034110111 is 11101143002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20034110111 - 214 = 20034093727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20034110101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017055055 + 10017055056.
It is an arithmetic number, because the mean of its divisors is an integer number (10017055056).
Almost surely, 220034110111 is an apocalyptic number.
20034110111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034110111 is an equidigital number, since it uses as much as digits as its factorization.
20034110111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 20034110111 its reverse (11101143002), we get a palindrome (31135253113).
It can be divided in two parts, 2003 and 4110111, that added together give a palindrome (4112114).
The spelling of 20034110111 in words is "twenty billion, thirty-four million, one hundred ten thousand, one hundred eleven".
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