Base | Representation |
---|---|
bin | 101101100011010110001100… |
… | …111100010101110010010111 |
3 | 222021100102102201002022100021 |
4 | 231203112030330111302113 |
5 | 202224342100210300124 |
6 | 1550031234241330011 |
7 | 60125111366616622 |
oct | 5543261474256227 |
9 | 867312381068307 |
10 | 200341114150039 |
11 | 5892020a068045 |
12 | 1a577549936907 |
13 | 87a3116c36505 |
14 | 37687c12b6db9 |
15 | 18264eae637e4 |
hex | b6358cf15c97 |
200341114150039 has 2 divisors, whose sum is σ = 200341114150040. Its totient is φ = 200341114150038.
The previous prime is 200341114150031. The next prime is 200341114150123. The reversal of 200341114150039 is 930051411143002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200341114150039 - 23 = 200341114150031 is a prime.
It is a super-3 number, since 3×2003411141500393 (a number of 44 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 200341114149986 and 200341114150013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200341114150031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100170557075019 + 100170557075020.
It is an arithmetic number, because the mean of its divisors is an integer number (100170557075020).
Almost surely, 2200341114150039 is an apocalyptic number.
200341114150039 is a deficient number, since it is larger than the sum of its proper divisors (1).
200341114150039 is an equidigital number, since it uses as much as digits as its factorization.
200341114150039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 200341114150039 in words is "two hundred trillion, three hundred forty-one billion, one hundred fourteen million, one hundred fifty thousand, thirty-nine".
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