Base | Representation |
---|---|
bin | 1001000111000100011101… |
… | …01011000010001011011101 |
3 | 2121221020120100100201010001 |
4 | 10203202032223002023131 |
5 | 10111214340001124313 |
6 | 110335314224014301 |
7 | 4135263124506214 |
oct | 443421653021335 |
9 | 77836510321101 |
10 | 20034121114333 |
11 | 6424472098287 |
12 | 22b68b6761391 |
13 | b242953c4711 |
14 | 4d3929b4607b |
15 | 24b2006aaadd |
hex | 12388eac22dd |
20034121114333 has 2 divisors, whose sum is σ = 20034121114334. Its totient is φ = 20034121114332.
The previous prime is 20034121114307. The next prime is 20034121114409. The reversal of 20034121114333 is 33341112143002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13792808093689 + 6241313020644 = 3713867^2 + 2498262^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20034121114333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20034121144333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017060557166 + 10017060557167.
It is an arithmetic number, because the mean of its divisors is an integer number (10017060557167).
Almost surely, 220034121114333 is an apocalyptic number.
It is an amenable number.
20034121114333 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034121114333 is an equidigital number, since it uses as much as digits as its factorization.
20034121114333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 20034121114333 its reverse (33341112143002), we get a palindrome (53375233257335).
The spelling of 20034121114333 in words is "twenty trillion, thirty-four billion, one hundred twenty-one million, one hundred fourteen thousand, three hundred thirty-three".
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