Base | Representation |
---|---|
bin | 1001000111000100110100… |
… | …01001000000110000011111 |
3 | 2121221021001202102001002121 |
4 | 10203202122021000300133 |
5 | 10111220233230202312 |
6 | 110335345300003411 |
7 | 4135300652113135 |
oct | 443423211006037 |
9 | 77837052361077 |
10 | 20034313522207 |
11 | 6424560765156 |
12 | 22b694b090567 |
13 | b242c622112a |
14 | 4d394750d755 |
15 | 24b212515707 |
hex | 12389a240c1f |
20034313522207 has 2 divisors, whose sum is σ = 20034313522208. Its totient is φ = 20034313522206.
The previous prime is 20034313522187. The next prime is 20034313522217. The reversal of 20034313522207 is 70222531343002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20034313522207 - 223 = 20034305133599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20034313522217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017156761103 + 10017156761104.
It is an arithmetic number, because the mean of its divisors is an integer number (10017156761104).
Almost surely, 220034313522207 is an apocalyptic number.
20034313522207 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034313522207 is an equidigital number, since it uses as much as digits as its factorization.
20034313522207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 34.
Adding to 20034313522207 its reverse (70222531343002), we get a palindrome (90256844865209).
The spelling of 20034313522207 in words is "twenty trillion, thirty-four billion, three hundred thirteen million, five hundred twenty-two thousand, two hundred seven".
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