200344421004133 has 4 divisors (see below), whose sum is σ = 228965052576160. Its totient is φ = 171723789432108.

The previous prime is 200344421004131. The next prime is 200344421004137. The reversal of 200344421004133 is 331400124443002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200344421004133 - 2¹ = 200344421004131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200344421004095 and 200344421004104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200344421004131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14310315786003 + ... + 14310315786016.

It is an arithmetic number, because the mean of its divisors is an integer number (57241263144040).

Almost surely, 2^{200344421004133} is an apocalyptic number.

It is an amenable number.

200344421004133 is a deficient number, since it is larger than the sum of its proper divisors (28620631572027).

200344421004133 is an equidigital number, since it uses as much as digits as its factorization.

200344421004133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28620631572026.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 200344421004133 its reverse (331400124443002), we get a palindrome (531744545447135).

The spelling of 200344421004133 in words is "two hundred trillion, three hundred forty-four billion, four hundred twenty-one million, four thousand, one hundred thirty-three".