Base | Representation |
---|---|
bin | 101101100011011001010010… |
… | …000011011110000010100011 |
3 | 222021100201222011202022120111 |
4 | 231203121102003132002203 |
5 | 202224420333302133103 |
6 | 1550032542333352151 |
7 | 60125256343524034 |
oct | 5543312203360243 |
9 | 867321864668514 |
10 | 200344421130403 |
11 | 5892165683a370 |
12 | 1a578111338657 |
13 | 87a35230c0b24 |
14 | 3768a1658ca8b |
15 | 182664144486d |
hex | b636520de0a3 |
200344421130403 has 8 divisors (see below), whose sum is σ = 218940313116096. Its totient is φ = 181812322943400.
The previous prime is 200344421130367. The next prime is 200344421130407. The reversal of 200344421130403 is 304031124443002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200344421130403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200344421130407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15948443101 + ... + 15948455662.
It is an arithmetic number, because the mean of its divisors is an integer number (27367539139512).
Almost surely, 2200344421130403 is an apocalyptic number.
200344421130403 is a deficient number, since it is larger than the sum of its proper divisors (18595891985693).
200344421130403 is a wasteful number, since it uses less digits than its factorization.
200344421130403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31896899345.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 200344421130403 its reverse (304031124443002), we get a palindrome (504375545573405).
The spelling of 200344421130403 in words is "two hundred trillion, three hundred forty-four billion, four hundred twenty-one million, one hundred thirty thousand, four hundred three".
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