Base | Representation |
---|---|
bin | 1001000111000101000011… |
… | …10100101110010010101111 |
3 | 2121221021101201221210120122 |
4 | 10203202201310232102233 |
5 | 10111221014224441143 |
6 | 110335410142435155 |
7 | 4135304105540453 |
oct | 443424164562257 |
9 | 77837351853518 |
10 | 20034442421423 |
11 | 64246174a5031 |
12 | 22b6986292abb |
13 | b24316b42861 |
14 | 4d395a6a4663 |
15 | 24b21d9c7c68 |
hex | 1238a1d2e4af |
20034442421423 has 2 divisors, whose sum is σ = 20034442421424. Its totient is φ = 20034442421422.
The previous prime is 20034442421381. The next prime is 20034442421429. The reversal of 20034442421423 is 32412424443002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20034442421423 - 28 = 20034442421167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20034442421429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017221210711 + 10017221210712.
It is an arithmetic number, because the mean of its divisors is an integer number (10017221210712).
Almost surely, 220034442421423 is an apocalyptic number.
20034442421423 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034442421423 is an equidigital number, since it uses as much as digits as its factorization.
20034442421423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 147456, while the sum is 35.
Adding to 20034442421423 its reverse (32412424443002), we get a palindrome (52446866864425).
The spelling of 20034442421423 in words is "twenty trillion, thirty-four billion, four hundred forty-two million, four hundred twenty-one thousand, four hundred twenty-three".
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