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2003451055 = 54373127649
BaseRepresentation
bin111011101101010…
…0011110010101111
312011121211212011221
41313122203302233
513100340413210
6530444524211
7100435024114
oct16732436257
95147755157
102003451055
11938994481
1247ab50667
1325c0b50c8
1415011690b
15bad451da
hex776a3caf

2003451055 has 16 divisors (see below), whose sum is σ = 2493770400. Its totient is φ = 1544030208.

The previous prime is 2003451053. The next prime is 2003451059. The reversal of 2003451055 is 5501543002.

It is a cyclic number.

It is not a de Polignac number, because 2003451055 - 21 = 2003451053 is a prime.

It is a super-2 number, since 2×20034510552 = 8027632259561226050, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003451053) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48130 + ... + 79519.

It is an arithmetic number, because the mean of its divisors is an integer number (155860650).

Almost surely, 22003451055 is an apocalyptic number.

2003451055 is a deficient number, since it is larger than the sum of its proper divisors (490319345).

2003451055 is a wasteful number, since it uses less digits than its factorization.

2003451055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 127770.

The product of its (nonzero) digits is 3000, while the sum is 25.

The square root of 2003451055 is about 44759.9268877866. The cubic root of 2003451055 is about 1260.6453096176.

Adding to 2003451055 its reverse (5501543002), we get a palindrome (7504994057).

The spelling of 2003451055 in words is "two billion, three million, four hundred fifty-one thousand, fifty-five".

Divisors: 1 5 43 73 215 365 3139 15695 127649 638245 5488907 9318377 27444535 46591885 400690211 2003451055