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20034555111157 is a prime number
BaseRepresentation
bin1001000111000101010001…
…00010100110011011110101
32121221021200121000000211111
410203202220202212123311
510111221232102024112
6110335425250035021
74135306644434116
oct443425042463365
977837617000744
1020034555111157
116424675073544
1222b69b7b78a71
13b243342aa282
144d396b63a20d
1524b2288375a7
hex1238a88a66f5

20034555111157 has 2 divisors, whose sum is σ = 20034555111158. Its totient is φ = 20034555111156.

The previous prime is 20034555111149. The next prime is 20034555111271. The reversal of 20034555111157 is 75111155543002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19930813787236 + 103741323921 = 4464394^2 + 322089^2 .

It is a cyclic number.

It is not a de Polignac number, because 20034555111157 - 23 = 20034555111149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20034585111157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017277555578 + 10017277555579.

It is an arithmetic number, because the mean of its divisors is an integer number (10017277555579).

Almost surely, 220034555111157 is an apocalyptic number.

It is an amenable number.

20034555111157 is a deficient number, since it is larger than the sum of its proper divisors (1).

20034555111157 is an equidigital number, since it uses as much as digits as its factorization.

20034555111157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 105000, while the sum is 40.

The spelling of 20034555111157 in words is "twenty trillion, thirty-four billion, five hundred fifty-five million, one hundred eleven thousand, one hundred fifty-seven".