Base | Representation |
---|---|
bin | 1001000111000110001001… |
… | …11011001101101010000001 |
3 | 2121221022220210002012211211 |
4 | 10203203010323031222001 |
5 | 10111223221004402223 |
6 | 110335544421010121 |
7 | 4135324516253434 |
oct | 443430473155201 |
9 | 77838823065754 |
10 | 20035031325313 |
11 | 6424899964264 |
12 | 22b6b0b553941 |
13 | b243abb549b4 |
14 | 4d39b499d81b |
15 | 24b255552d0d |
hex | 1238c4ecda81 |
20035031325313 has 2 divisors, whose sum is σ = 20035031325314. Its totient is φ = 20035031325312.
The previous prime is 20035031325299. The next prime is 20035031325349. The reversal of 20035031325313 is 31352313053002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13792993787664 + 6242037537649 = 3713892^2 + 2498407^2 .
It is a cyclic number.
It is not a de Polignac number, because 20035031325313 - 29 = 20035031324801 is a prime.
It is a super-3 number, since 3×200350313253133 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (20035031320313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017515662656 + 10017515662657.
It is an arithmetic number, because the mean of its divisors is an integer number (10017515662657).
Almost surely, 220035031325313 is an apocalyptic number.
It is an amenable number.
20035031325313 is a deficient number, since it is larger than the sum of its proper divisors (1).
20035031325313 is an equidigital number, since it uses as much as digits as its factorization.
20035031325313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 20035031325313 its reverse (31352313053002), we get a palindrome (51387344378315).
The spelling of 20035031325313 in words is "twenty trillion, thirty-five billion, thirty-one million, three hundred twenty-five thousand, three hundred thirteen".
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