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20035031325349 is a prime number
BaseRepresentation
bin1001000111000110001001…
…11011001101101010100101
32121221022220210002012220011
410203203010323031222211
510111223221004402344
6110335544421010221
74135324516253515
oct443430473155245
977838823065804
1020035031325349
116424899964297
1222b6b0b553971
13b243abb54a11
144d39b499d845
1524b255552d34
hex1238c4ecdaa5

20035031325349 has 2 divisors, whose sum is σ = 20035031325350. Its totient is φ = 20035031325348.

The previous prime is 20035031325313. The next prime is 20035031325371. The reversal of 20035031325349 is 94352313053002.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15749841520449 + 4285189804900 = 3968607^2 + 2070070^2 .

It is a cyclic number.

It is not a de Polignac number, because 20035031325349 - 213 = 20035031317157 is a prime.

It is a super-3 number, since 3×200350313253493 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20035031025349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017515662674 + 10017515662675.

It is an arithmetic number, because the mean of its divisors is an integer number (10017515662675).

Almost surely, 220035031325349 is an apocalyptic number.

It is an amenable number.

20035031325349 is a deficient number, since it is larger than the sum of its proper divisors (1).

20035031325349 is an equidigital number, since it uses as much as digits as its factorization.

20035031325349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 40.

The spelling of 20035031325349 in words is "twenty trillion, thirty-five billion, thirty-one million, three hundred twenty-five thousand, three hundred forty-nine".