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20035315145 = 54007063029
BaseRepresentation
bin10010101010001100…
…101010010111001001
31220201021222110112002
4102222030222113021
5312013020041040
613112030200345
71306331240336
oct225214522711
956637873462
1020035315145
11855145a89a
123a719530b5
131b73ac0c81
14d80c7998d
157c3de4a15
hex4aa32a5c9

20035315145 has 4 divisors (see below), whose sum is σ = 24042378180. Its totient is φ = 16028252112.

The previous prime is 20035315081. The next prime is 20035315171. The reversal of 20035315145 is 54151353002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9453283984 + 10582031161 = 97228^2 + 102869^2 .

It is a cyclic number.

It is not a de Polignac number, because 20035315145 - 26 = 20035315081 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003531510 + ... + 2003531519.

It is an arithmetic number, because the mean of its divisors is an integer number (6010594545).

Almost surely, 220035315145 is an apocalyptic number.

It is an amenable number.

20035315145 is a deficient number, since it is larger than the sum of its proper divisors (4007063035).

20035315145 is an equidigital number, since it uses as much as digits as its factorization.

20035315145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4007063034.

The product of its (nonzero) digits is 9000, while the sum is 29.

Adding to 20035315145 its reverse (54151353002), we get a palindrome (74186668147).

The spelling of 20035315145 in words is "twenty billion, thirty-five million, three hundred fifteen thousand, one hundred forty-five".

Divisors: 1 5 4007063029 20035315145