Base | Representation |
---|---|
bin | 1001000111001000001111… |
… | …10111000100011001001111 |
3 | 2121221102211001011212100101 |
4 | 10203210013313010121033 |
5 | 10111233021000443041 |
6 | 110340252054311531 |
7 | 4135364403426046 |
oct | 443440767043117 |
9 | 77842731155311 |
10 | 20036154312271 |
11 | 6425315849a59 |
12 | 22b71836585a7 |
13 | b2452a6c3516 |
14 | 4d3a7dba355d |
15 | 24b2bde29b31 |
hex | 123907dc464f |
20036154312271 has 2 divisors, whose sum is σ = 20036154312272. Its totient is φ = 20036154312270.
The previous prime is 20036154312197. The next prime is 20036154312277. The reversal of 20036154312271 is 17221345163002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20036154312271 - 213 = 20036154304079 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20036154312271.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20036154312277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10018077156135 + 10018077156136.
It is an arithmetic number, because the mean of its divisors is an integer number (10018077156136).
Almost surely, 220036154312271 is an apocalyptic number.
20036154312271 is a deficient number, since it is larger than the sum of its proper divisors (1).
20036154312271 is an equidigital number, since it uses as much as digits as its factorization.
20036154312271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 37.
Adding to 20036154312271 its reverse (17221345163002), we get a palindrome (37257499475273).
The spelling of 20036154312271 in words is "twenty trillion, thirty-six billion, one hundred fifty-four million, three hundred twelve thousand, two hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •