Base | Representation |
---|---|
bin | 11101001010001110010… |
… | …010100101010010001101 |
3 | 21002120021012020110120011 |
4 | 131022032102211102031 |
5 | 230312332022332132 |
6 | 4132315144153221 |
7 | 264526033634236 |
oct | 35121622452215 |
9 | 7076235213504 |
10 | 2003841995917 |
11 | 702908626223 |
12 | 284436768811 |
13 | 116c66513938 |
14 | 6cdb4c3408d |
15 | 371d0441b47 |
hex | 1d28e4a548d |
2003841995917 has 2 divisors, whose sum is σ = 2003841995918. Its totient is φ = 2003841995916.
The previous prime is 2003841995891. The next prime is 2003841996001. The reversal of 2003841995917 is 7195991483002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1431865919236 + 571976076681 = 1196606^2 + 756291^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2003841995917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003841995017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001920997958 + 1001920997959.
It is an arithmetic number, because the mean of its divisors is an integer number (1001920997959).
Almost surely, 22003841995917 is an apocalyptic number.
It is an amenable number.
2003841995917 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003841995917 is an equidigital number, since it uses as much as digits as its factorization.
2003841995917 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4898880, while the sum is 58.
The spelling of 2003841995917 in words is "two trillion, three billion, eight hundred forty-one million, nine hundred ninety-five thousand, nine hundred seventeen".
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