Base | Representation |
---|---|
bin | 1001000111001110101011… |
… | …01010011101110010000011 |
3 | 2121221202201200020102002121 |
4 | 10203213111222131302003 |
5 | 10111312103410134013 |
6 | 110342022440025111 |
7 | 4135546100653006 |
oct | 443472552356203 |
9 | 77852650212077 |
10 | 20039607114883 |
11 | 642682786a734 |
12 | 22b7987a62197 |
13 | b2495ab462a5 |
14 | 4d3cca59753d |
15 | 24b42211258d |
hex | 1239d5a9dc83 |
20039607114883 has 2 divisors, whose sum is σ = 20039607114884. Its totient is φ = 20039607114882.
The previous prime is 20039607114851. The next prime is 20039607114907. The reversal of 20039607114883 is 38841170693002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20039607114883 - 25 = 20039607114851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20039607114883.
It is not a weakly prime, because it can be changed into another prime (20039607714883) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10019803557441 + 10019803557442.
It is an arithmetic number, because the mean of its divisors is an integer number (10019803557442).
Almost surely, 220039607114883 is an apocalyptic number.
20039607114883 is a deficient number, since it is larger than the sum of its proper divisors (1).
20039607114883 is an equidigital number, since it uses as much as digits as its factorization.
20039607114883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1741824, while the sum is 52.
The spelling of 20039607114883 in words is "twenty trillion, thirty-nine billion, six hundred seven million, one hundred fourteen thousand, eight hundred eighty-three".
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