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200399999 is a prime number
BaseRepresentation
bin10111111000111…
…01110001111111
3111222002101010012
423330131301333
5402300244444
631515133435
74652241362
oct1374356177
9458071105
10200399999
11a3136538
125714427b
13326973a7
141c8880d9
15128d7b9e
hexbf1dc7f

200399999 has 2 divisors, whose sum is σ = 200400000. Its totient is φ = 200399998.

The previous prime is 200399977. The next prime is 200400007. The reversal of 200399999 is 999993002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 200399999 - 28 = 200399743 is a prime.

200399999 is a modest number, since divided by 99999 gives 2003 as remainder.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200399939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100199999 + 100200000.

It is an arithmetic number, because the mean of its divisors is an integer number (100200000).

Almost surely, 2200399999 is an apocalyptic number.

200399999 is a deficient number, since it is larger than the sum of its proper divisors (1).

200399999 is an equidigital number, since it uses as much as digits as its factorization.

200399999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 354294, while the sum is 50.

The square root of 200399999 is about 14156.2706600291. The cubic root of 200399999 is about 585.1931560767.

The spelling of 200399999 in words is "two hundred million, three hundred ninety-nine thousand, nine hundred ninety-nine".