Base | Representation |
---|---|
bin | 10111111000111… |
… | …10010011000001 |
3 | 111222002111000111 |
4 | 23330132103001 |
5 | 402300331423 |
6 | 31515151321 |
7 | 4652250502 |
oct | 1374362301 |
9 | 458074014 |
10 | 200402113 |
11 | a313808a |
12 | 57145541 |
13 | 32698342 |
14 | 1c888ba9 |
15 | 128d860d |
hex | bf1e4c1 |
200402113 has 2 divisors, whose sum is σ = 200402114. Its totient is φ = 200402112.
The previous prime is 200402107. The next prime is 200402117. The reversal of 200402113 is 311204002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 119617969 + 80784144 = 10937^2 + 8988^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200402113 is a prime.
It is a super-2 number, since 2×2004021132 = 80322013789729538, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 200402093 and 200402102.
It is not a weakly prime, because it can be changed into another prime (200402117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100201056 + 100201057.
It is an arithmetic number, because the mean of its divisors is an integer number (100201057).
Almost surely, 2200402113 is an apocalyptic number.
It is an amenable number.
200402113 is a deficient number, since it is larger than the sum of its proper divisors (1).
200402113 is an equidigital number, since it uses as much as digits as its factorization.
200402113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
The square root of 200402113 is about 14156.3453263899. The cubic root of 200402113 is about 585.1952137846.
Adding to 200402113 its reverse (311204002), we get a palindrome (511606115).
The spelling of 200402113 in words is "two hundred million, four hundred two thousand, one hundred thirteen".
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