Base | Representation |
---|---|
bin | 11101001010011001011… |
… | …111001111100000100101 |
3 | 21002120202021202011002022 |
4 | 131022121133033200211 |
5 | 230313223121121343 |
6 | 4132345534552525 |
7 | 264533504532434 |
oct | 35123137174045 |
9 | 7076667664068 |
10 | 2004029863973 |
11 | 7029a4682285 |
12 | 284489668745 |
13 | 116c96410b77 |
14 | 6cdd1b7911b |
15 | 371e1ba1568 |
hex | 1d2997cf825 |
2004029863973 has 2 divisors, whose sum is σ = 2004029863974. Its totient is φ = 2004029863972.
The previous prime is 2004029863879. The next prime is 2004029864021. The reversal of 2004029863973 is 3793689204002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1121974548289 + 882055315684 = 1059233^2 + 939178^2 .
It is a cyclic number.
It is not a de Polignac number, because 2004029863973 - 240 = 904518236197 is a prime.
It is a super-2 number, since 2×20040298639732 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2004029863673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002014931986 + 1002014931987.
It is an arithmetic number, because the mean of its divisors is an integer number (1002014931987).
Almost surely, 22004029863973 is an apocalyptic number.
It is an amenable number.
2004029863973 is a deficient number, since it is larger than the sum of its proper divisors (1).
2004029863973 is an equidigital number, since it uses as much as digits as its factorization.
2004029863973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3919104, while the sum is 53.
The spelling of 2004029863973 in words is "two trillion, four billion, twenty-nine million, eight hundred sixty-three thousand, nine hundred seventy-three".
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