Base | Representation |
---|---|
bin | 1001000111001111111111… |
… | …01100111010110010011011 |
3 | 2121221211112211100122211112 |
4 | 10203213333230322302123 |
5 | 10111320024433313201 |
6 | 110342220432450535 |
7 | 4135602423541625 |
oct | 443477754726233 |
9 | 77854484318745 |
10 | 20040312401051 |
11 | 642705999a668 |
12 | 22b7b440a9a4b |
13 | b24a40cb6797 |
14 | 4d3d56109c15 |
15 | 24b463ecb0bb |
hex | 1239ffb3ac9b |
20040312401051 has 4 divisors (see below), whose sum is σ = 20046149955432. Its totient is φ = 20034474846672.
The previous prime is 20040312401047. The next prime is 20040312401059. The reversal of 20040312401051 is 15010421304002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20040312401051 - 22 = 20040312401047 is a prime.
It is a super-2 number, since 2×200403124010512 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20040312401059) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2918772041 + ... + 2918778906.
It is an arithmetic number, because the mean of its divisors is an integer number (5011537488858).
Almost surely, 220040312401051 is an apocalyptic number.
20040312401051 is a deficient number, since it is larger than the sum of its proper divisors (5837554381).
20040312401051 is an equidigital number, since it uses as much as digits as its factorization.
20040312401051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5837554380.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 20040312401051 its reverse (15010421304002), we get a palindrome (35050733705053).
The spelling of 20040312401051 in words is "twenty trillion, forty billion, three hundred twelve million, four hundred one thousand, fifty-one".
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