Base | Representation |
---|---|
bin | 1011101010100101011… |
… | …1100110111111010011 |
3 | 201011021220211120120201 |
4 | 2322221113212333103 |
5 | 11240414432043011 |
6 | 232022254320031 |
7 | 20323230116536 |
oct | 2725127467723 |
9 | 634256746521 |
10 | 200410034131 |
11 | 77aa226a98a |
12 | 32a10ab9017 |
13 | 15b8b264a18 |
14 | 99b2738a1d |
15 | 532e46acc1 |
hex | 2ea95e6fd3 |
200410034131 has 2 divisors, whose sum is σ = 200410034132. Its totient is φ = 200410034130.
The previous prime is 200410034053. The next prime is 200410034177. The reversal of 200410034131 is 131430014002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200410034131 - 27 = 200410034003 is a prime.
It is a super-2 number, since 2×2004100341312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 200410034099 and 200410034108.
It is not a weakly prime, because it can be changed into another prime (200410034191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100205017065 + 100205017066.
It is an arithmetic number, because the mean of its divisors is an integer number (100205017066).
Almost surely, 2200410034131 is an apocalyptic number.
200410034131 is a deficient number, since it is larger than the sum of its proper divisors (1).
200410034131 is an equidigital number, since it uses as much as digits as its factorization.
200410034131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 200410034131 its reverse (131430014002), we get a palindrome (331840048133).
The spelling of 200410034131 in words is "two hundred billion, four hundred ten million, thirty-four thousand, one hundred thirty-one".
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