Base | Representation |
---|---|
bin | 10010101010100011… |
… | …010011100110100001 |
3 | 1220201201011001022012 |
4 | 102222203103212201 |
5 | 312021030014413 |
6 | 13112401322305 |
7 | 1306432552613 |
oct | 225243234641 |
9 | 56651131265 |
10 | 20041251233 |
11 | 8554844753 |
12 | 3a73936395 |
13 | 1b750bbb53 |
14 | d81982db3 |
15 | 7c46b87a8 |
hex | 4aa8d39a1 |
20041251233 has 2 divisors, whose sum is σ = 20041251234. Its totient is φ = 20041251232.
The previous prime is 20041251211. The next prime is 20041251353. The reversal of 20041251233 is 33215214002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20035836304 + 5414929 = 141548^2 + 2327^2 .
It is a cyclic number.
It is not a de Polignac number, because 20041251233 - 212 = 20041247137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20041251199 and 20041251208.
It is not a weakly prime, because it can be changed into another prime (20041251203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10020625616 + 10020625617.
It is an arithmetic number, because the mean of its divisors is an integer number (10020625617).
Almost surely, 220041251233 is an apocalyptic number.
It is an amenable number.
20041251233 is a deficient number, since it is larger than the sum of its proper divisors (1).
20041251233 is an equidigital number, since it uses as much as digits as its factorization.
20041251233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 20041251233 its reverse (33215214002), we get a palindrome (53256465235).
The spelling of 20041251233 in words is "twenty billion, forty-one million, two hundred fifty-one thousand, two hundred thirty-three".
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