Base | Representation |
---|---|
bin | 1011101010100110001… |
… | …1100010111010000111 |
3 | 201011022010201112210001 |
4 | 2322221203202322013 |
5 | 11240421232210033 |
6 | 232022445342131 |
7 | 20323265531164 |
oct | 2725143427207 |
9 | 634263645701 |
10 | 200413163143 |
11 | 77aa4007846 |
12 | 32a11b67947 |
13 | 15b8babbccb |
14 | 99b2d1106b |
15 | 532e887e7d |
hex | 2ea98e2e87 |
200413163143 has 2 divisors, whose sum is σ = 200413163144. Its totient is φ = 200413163142.
The previous prime is 200413163087. The next prime is 200413163173. The reversal of 200413163143 is 341361314002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200413163143 - 213 = 200413154951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200413163173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100206581571 + 100206581572.
It is an arithmetic number, because the mean of its divisors is an integer number (100206581572).
Almost surely, 2200413163143 is an apocalyptic number.
200413163143 is a deficient number, since it is larger than the sum of its proper divisors (1).
200413163143 is an equidigital number, since it uses as much as digits as its factorization.
200413163143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 200413163143 its reverse (341361314002), we get a palindrome (541774477145).
The spelling of 200413163143 in words is "two hundred billion, four hundred thirteen million, one hundred sixty-three thousand, one hundred forty-three".
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