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200413413397 is a prime number
BaseRepresentation
bin1011101010100110010…
…0100000000000010101
3201011022011012021001201
42322221210200000111
511240421313212042
6232022454552501
720323300622611
oct2725144400025
9634264167051
10200413413397
1177aa416886a
1232a12068731
1315b8bb78ba2
1499b2d78341
15532e8d71b7
hex2ea9920015

200413413397 has 2 divisors, whose sum is σ = 200413413398. Its totient is φ = 200413413396.

The previous prime is 200413413379. The next prime is 200413413511. The reversal of 200413413397 is 793314314002.

Together with previous prime (200413413379) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 196008967441 + 4404445956 = 442729^2 + 66366^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200413413397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200413413307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100206706698 + 100206706699.

It is an arithmetic number, because the mean of its divisors is an integer number (100206706699).

Almost surely, 2200413413397 is an apocalyptic number.

It is an amenable number.

200413413397 is a deficient number, since it is larger than the sum of its proper divisors (1).

200413413397 is an equidigital number, since it uses as much as digits as its factorization.

200413413397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 37.

Adding to 200413413397 its reverse (793314314002), we get a palindrome (993727727399).

The spelling of 200413413397 in words is "two hundred billion, four hundred thirteen million, four hundred thirteen thousand, three hundred ninety-seven".