Search a number
-
+
20042012031 = 36680670677
BaseRepresentation
bin10010101010100110…
…001101010101111111
31220201202120200220220
4102222212031111333
5312021223341111
613112425512423
71306442201646
oct225246152577
956652520826
1020042012031
118555214308
123a74042713
131b752c7222
14d81b0035d
157c47b8e06
hex4aa98d57f

20042012031 has 4 divisors (see below), whose sum is σ = 26722682712. Its totient is φ = 13361341352.

The previous prime is 20042012009. The next prime is 20042012051. The reversal of 20042012031 is 13021024002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20042012031 - 25 = 20042011999 is a prime.

It is a super-2 number, since 2×200420120312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 20042012031.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20042012051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3340335336 + ... + 3340335341.

It is an arithmetic number, because the mean of its divisors is an integer number (6680670678).

Almost surely, 220042012031 is an apocalyptic number.

20042012031 is a deficient number, since it is larger than the sum of its proper divisors (6680670681).

20042012031 is an equidigital number, since it uses as much as digits as its factorization.

20042012031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6680670680.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 20042012031 its reverse (13021024002), we get a palindrome (33063036033).

The spelling of 20042012031 in words is "twenty billion, forty-two million, twelve thousand, thirty-one".

Divisors: 1 3 6680670677 20042012031