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20044104403 = 31646584013
BaseRepresentation
bin10010101010101110…
…001100001011010011
31220201220112000010011
4102222232030023103
5312022242320103
613112542415351
71306466035111
oct225256141323
956656460104
1020044104403
118556413344
123a74891557
131b7587a70b
14d820c6ab1
157c4a7dd6d
hex4aab8c2d3

20044104403 has 4 divisors (see below), whose sum is σ = 20690688448. Its totient is φ = 19397520360.

The previous prime is 20044104383. The next prime is 20044104413. The reversal of 20044104403 is 30440144002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20044104403 - 217 = 20043973331 is a prime.

It is a super-2 number, since 2×200441044032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20044104413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 323291976 + ... + 323292037.

It is an arithmetic number, because the mean of its divisors is an integer number (5172672112).

Almost surely, 220044104403 is an apocalyptic number.

20044104403 is a deficient number, since it is larger than the sum of its proper divisors (646584045).

20044104403 is an equidigital number, since it uses as much as digits as its factorization.

20044104403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 646584044.

The product of its (nonzero) digits is 1536, while the sum is 22.

Adding to 20044104403 its reverse (30440144002), we get a palindrome (50484248405).

The spelling of 20044104403 in words is "twenty billion, forty-four million, one hundred four thousand, four hundred three".

Divisors: 1 31 646584013 20044104403