Base | Representation |
---|---|
bin | 1011101010101100111… |
… | …1110010111010011011 |
3 | 201011101010010020212001 |
4 | 2322223033302322123 |
5 | 11241001013242001 |
6 | 232025341501431 |
7 | 20324061660241 |
oct | 2725317627233 |
9 | 634333106761 |
10 | 200441540251 |
11 | 780090299a7 |
12 | 32a1b571877 |
13 | 15b949463b4 |
14 | 99b69ba791 |
15 | 53320e1001 |
hex | 2eab3f2e9b |
200441540251 has 2 divisors, whose sum is σ = 200441540252. Its totient is φ = 200441540250.
The previous prime is 200441540237. The next prime is 200441540323. The reversal of 200441540251 is 152045144002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200441540251 - 223 = 200433151643 is a prime.
It is a super-2 number, since 2×2004415402512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200441549251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100220770125 + 100220770126.
It is an arithmetic number, because the mean of its divisors is an integer number (100220770126).
Almost surely, 2200441540251 is an apocalyptic number.
200441540251 is a deficient number, since it is larger than the sum of its proper divisors (1).
200441540251 is an equidigital number, since it uses as much as digits as its factorization.
200441540251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6400, while the sum is 28.
Adding to 200441540251 its reverse (152045144002), we get a palindrome (352486684253).
The spelling of 200441540251 in words is "two hundred billion, four hundred forty-one million, five hundred forty thousand, two hundred fifty-one".
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