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2004600041153 is a prime number
BaseRepresentation
bin11101001010111011011…
…110010010111011000001
321002122020000122011010122
4131022323132102323001
5230320410102304103
64132522303510025
7264553600131533
oct35127336227301
97078200564118
102004600041153
11703167510896
122846085b8315
13117057597308
146d04779b853
1537226c7cb38
hex1d2bb792ec1

2004600041153 has 2 divisors, whose sum is σ = 2004600041154. Its totient is φ = 2004600041152.

The previous prime is 2004600041117. The next prime is 2004600041203. The reversal of 2004600041153 is 3511400064002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1808734491664 + 195865549489 = 1344892^2 + 442567^2 .

It is a cyclic number.

It is not a de Polignac number, because 2004600041153 - 218 = 2004599779009 is a prime.

It is a super-4 number, since 4×20046000411534 (a number of 50 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (2004600001153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002300020576 + 1002300020577.

It is an arithmetic number, because the mean of its divisors is an integer number (1002300020577).

Almost surely, 22004600041153 is an apocalyptic number.

It is an amenable number.

2004600041153 is a deficient number, since it is larger than the sum of its proper divisors (1).

2004600041153 is an equidigital number, since it uses as much as digits as its factorization.

2004600041153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 26.

The spelling of 2004600041153 in words is "two trillion, four billion, six hundred million, forty-one thousand, one hundred fifty-three".