Base | Representation |
---|---|
bin | 11101001010111101010… |
… | …110101111010101111111 |
3 | 21002122022020001021002201 |
4 | 131022331112233111333 |
5 | 230320441143133342 |
6 | 4132525352332331 |
7 | 264554432403241 |
oct | 35127526572577 |
9 | 7078266037081 |
10 | 2004631614847 |
11 | 703183316654 |
12 | 2846170a40a7 |
13 | 117060ca0684 |
14 | 6d04ba5a091 |
15 | 37229917db7 |
hex | 1d2bd5af57f |
2004631614847 has 2 divisors, whose sum is σ = 2004631614848. Its totient is φ = 2004631614846.
The previous prime is 2004631614833. The next prime is 2004631614911. The reversal of 2004631614847 is 7484161364002.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2004631614847 is a prime.
It is a super-2 number, since 2×20046316148472 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2004631614797 and 2004631614806.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2004631614827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002315807423 + 1002315807424.
It is an arithmetic number, because the mean of its divisors is an integer number (1002315807424).
Almost surely, 22004631614847 is an apocalyptic number.
2004631614847 is a deficient number, since it is larger than the sum of its proper divisors (1).
2004631614847 is an equidigital number, since it uses as much as digits as its factorization.
2004631614847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 774144, while the sum is 46.
Adding to 2004631614847 its reverse (7484161364002), we get a palindrome (9488792978849).
The spelling of 2004631614847 in words is "two trillion, four billion, six hundred thirty-one million, six hundred fourteen thousand, eight hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •