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2005014031981 is a prime number
BaseRepresentation
bin11101001011010100001…
…001100010111001101101
321002200021212122001210021
4131023110021202321231
5230322232043010411
64133031333042141
7264600055034062
oct35132411427155
97080255561707
102005014031981
1170335a172274
12284703186351
131170c2296abc
146d086764c69
153724d2a6a71
hex1d2d4262e6d

2005014031981 has 2 divisors, whose sum is σ = 2005014031982. Its totient is φ = 2005014031980.

The previous prime is 2005014031961. The next prime is 2005014031997. The reversal of 2005014031981 is 1891304105002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1550547944100 + 454466087881 = 1245210^2 + 674141^2 .

It is a cyclic number.

It is not a de Polignac number, because 2005014031981 - 215 = 2005013999213 is a prime.

It is a super-2 number, since 2×20050140319812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2005014031901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002507015990 + 1002507015991.

It is an arithmetic number, because the mean of its divisors is an integer number (1002507015991).

Almost surely, 22005014031981 is an apocalyptic number.

It is an amenable number.

2005014031981 is a deficient number, since it is larger than the sum of its proper divisors (1).

2005014031981 is an equidigital number, since it uses as much as digits as its factorization.

2005014031981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 34.

Adding to 2005014031981 its reverse (1891304105002), we get a palindrome (3896318136983).

The spelling of 2005014031981 in words is "two trillion, five billion, fourteen million, thirty-one thousand, nine hundred eighty-one".