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20050440433 is a prime number
BaseRepresentation
bin10010101011000110…
…010111000011110001
31220202100102220111221
4102223012113003301
5312030403043213
613113330305041
71306603634362
oct225306270361
956670386457
1020050440433
118559a50731
123a76a28181
131b76c8864a
14d82c95b69
157c53d138d
hex4ab1970f1

20050440433 has 2 divisors, whose sum is σ = 20050440434. Its totient is φ = 20050440432.

The previous prime is 20050440427. The next prime is 20050440437. The reversal of 20050440433 is 33404405002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19928404224 + 122036209 = 141168^2 + 11047^2 .

It is a cyclic number.

It is not a de Polignac number, because 20050440433 - 25 = 20050440401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20050440398 and 20050440407.

It is not a weakly prime, because it can be changed into another prime (20050440437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10025220216 + 10025220217.

It is an arithmetic number, because the mean of its divisors is an integer number (10025220217).

Almost surely, 220050440433 is an apocalyptic number.

It is an amenable number.

20050440433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20050440433 is an equidigital number, since it uses as much as digits as its factorization.

20050440433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 25.

Adding to 20050440433 its reverse (33404405002), we get a palindrome (53454845435).

The spelling of 20050440433 in words is "twenty billion, fifty million, four hundred forty thousand, four hundred thirty-three".