Base | Representation |
---|---|
bin | 10010101011001101… |
… | …000000000110111001 |
3 | 1220202110201100201102 |
4 | 102223031000012321 |
5 | 312031324301213 |
6 | 13113431501145 |
7 | 1306624505234 |
oct | 225315000671 |
9 | 56673640642 |
10 | 20052181433 |
11 | 855aa2a779 |
12 | 3a775277b5 |
13 | 1b77447c1b |
14 | d831ca41b |
15 | 7c5627158 |
hex | 4ab3401b9 |
20052181433 has 2 divisors, whose sum is σ = 20052181434. Its totient is φ = 20052181432.
The previous prime is 20052181417. The next prime is 20052181463. The reversal of 20052181433 is 33418125002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20027061289 + 25120144 = 141517^2 + 5012^2 .
It is a cyclic number.
It is not a de Polignac number, because 20052181433 - 24 = 20052181417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20052181396 and 20052181405.
It is not a weakly prime, because it can be changed into another prime (20052181463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10026090716 + 10026090717.
It is an arithmetic number, because the mean of its divisors is an integer number (10026090717).
Almost surely, 220052181433 is an apocalyptic number.
It is an amenable number.
20052181433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20052181433 is an equidigital number, since it uses as much as digits as its factorization.
20052181433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
The spelling of 20052181433 in words is "twenty billion, fifty-two million, one hundred eighty-one thousand, four hundred thirty-three".
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