Base | Representation |
---|---|
bin | 101101101101000110001011… |
… | …001101100001111101010011 |
3 | 222100201110210011122220121122 |
4 | 231231012023031201331103 |
5 | 202321331213100000313 |
6 | 1551303120255312455 |
7 | 60224400305442032 |
oct | 5555061315417523 |
9 | 870643704586548 |
10 | 201011100000083 |
11 | 5905936866862a |
12 | 1a66536a81b72b |
13 | 882135b0c58b9 |
14 | 378cdbc32c719 |
15 | 1838b60049708 |
hex | b6d18b361f53 |
201011100000083 has 2 divisors, whose sum is σ = 201011100000084. Its totient is φ = 201011100000082.
The previous prime is 201011100000013. The next prime is 201011100000131. The reversal of 201011100000083 is 380000001110102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201011100000083 - 230 = 201010026258259 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (201011100000013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100505550000041 + 100505550000042.
It is an arithmetic number, because the mean of its divisors is an integer number (100505550000042).
Almost surely, 2201011100000083 is an apocalyptic number.
201011100000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
201011100000083 is an equidigital number, since it uses as much as digits as its factorization.
201011100000083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 201011100000083 its reverse (380000001110102), we get a palindrome (581011101110185).
The spelling of 201011100000083 in words is "two hundred one trillion, eleven billion, one hundred million, eighty-three", and thus it is an aban number.
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