Base | Representation |
---|---|
bin | 111011111010000… |
… | …0000010011000101 |
3 | 12012002101202012020 |
4 | 1313310000103011 |
5 | 13104042341123 |
6 | 531243513353 |
7 | 100545515166 |
oct | 16764002305 |
9 | 5162352166 |
10 | 2010121413 |
11 | 94172aa73 |
12 | 481228859 |
13 | 2605ac271 |
14 | 150d7176d |
15 | bb7117e3 |
hex | 77d004c5 |
2010121413 has 4 divisors (see below), whose sum is σ = 2680161888. Its totient is φ = 1340080940.
The previous prime is 2010121339. The next prime is 2010121433. The reversal of 2010121413 is 3141210102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2010121413 - 225 = 1976566981 is a prime.
It is a super-2 number, since 2×20101214132 = 8081176190002233138, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2010121392 and 2010121401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2010121433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335020233 + ... + 335020238.
It is an arithmetic number, because the mean of its divisors is an integer number (670040472).
Almost surely, 22010121413 is an apocalyptic number.
It is an amenable number.
2010121413 is a deficient number, since it is larger than the sum of its proper divisors (670040475).
2010121413 is an equidigital number, since it uses as much as digits as its factorization.
2010121413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 670040474.
The product of its (nonzero) digits is 48, while the sum is 15.
The square root of 2010121413 is about 44834.3775801561. The cubic root of 2010121413 is about 1262.0428382095.
Adding to 2010121413 its reverse (3141210102), we get a palindrome (5151331515).
It can be divided in two parts, 20101 and 21413, that added together give a palindrome (41514).
The spelling of 2010121413 in words is "two billion, ten million, one hundred twenty-one thousand, four hundred thirteen".
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