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2010133113 = 32683249737
BaseRepresentation
bin111011111010000…
…0011001001111001
312012002102100020120
41313310003021321
513104043224423
6531244043453
7100545564252
oct16764031171
95162370216
102010133113
1194173883a
12481233589
132605b46a1
14150d75b29
15bb714ee3
hex77d03279

2010133113 has 8 divisors (see below), whose sum is σ = 2681187168. Its totient is φ = 1339583904.

The previous prime is 2010133109. The next prime is 2010133133. The reversal of 2010133113 is 3113310102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2010133113 - 22 = 2010133109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2010133092 and 2010133101.

It is not an unprimeable number, because it can be changed into a prime (2010133133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 116820 + ... + 132917.

It is an arithmetic number, because the mean of its divisors is an integer number (335148396).

Almost surely, 22010133113 is an apocalyptic number.

It is an amenable number.

2010133113 is a deficient number, since it is larger than the sum of its proper divisors (671054055).

2010133113 is a wasteful number, since it uses less digits than its factorization.

2010133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 252423.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 2010133113 is about 44834.5080601985. The cubic root of 2010133113 is about 1262.0452867967.

Adding to 2010133113 its reverse (3113310102), we get a palindrome (5123443215).

The spelling of 2010133113 in words is "two billion, ten million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 2683 8049 249737 749211 670044371 2010133113