Base | Representation |
---|---|
bin | 1011101100110111111… |
… | …1000000110001101011 |
3 | 201012212201202201010111 |
4 | 2323031333000301223 |
5 | 11243144212440042 |
6 | 232203241155151 |
7 | 20344366503115 |
oct | 2731577006153 |
9 | 635781681114 |
10 | 201024343147 |
11 | 78288001391 |
12 | 32b6278bab7 |
13 | 15c58600594 |
14 | 9a301683b5 |
15 | 5368363517 |
hex | 2ecdfc0c6b |
201024343147 has 2 divisors, whose sum is σ = 201024343148. Its totient is φ = 201024343146.
The previous prime is 201024343139. The next prime is 201024343207. The reversal of 201024343147 is 741343420102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201024343147 - 23 = 201024343139 is a prime.
It is not a weakly prime, because it can be changed into another prime (201024343127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100512171573 + 100512171574.
It is an arithmetic number, because the mean of its divisors is an integer number (100512171574).
Almost surely, 2201024343147 is an apocalyptic number.
201024343147 is a deficient number, since it is larger than the sum of its proper divisors (1).
201024343147 is an equidigital number, since it uses as much as digits as its factorization.
201024343147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 201024343147 its reverse (741343420102), we get a palindrome (942367763249).
The spelling of 201024343147 in words is "two hundred one billion, twenty-four million, three hundred forty-three thousand, one hundred forty-seven".
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