Base | Representation |
---|---|
bin | 1011101100111101101… |
… | …0000100000000001111 |
3 | 201012221101200100022111 |
4 | 2323033122010000033 |
5 | 11243221320231341 |
6 | 232205452524451 |
7 | 20345106413062 |
oct | 2731732040017 |
9 | 635841610274 |
10 | 201048211471 |
11 | 7829a523a78 |
12 | 32b6a780727 |
13 | 15c60539653 |
14 | 9a333bc8d9 |
15 | 536a4ca681 |
hex | 2ecf68400f |
201048211471 has 2 divisors, whose sum is σ = 201048211472. Its totient is φ = 201048211470.
The previous prime is 201048211453. The next prime is 201048211499. The reversal of 201048211471 is 174112840102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201048211471 - 25 = 201048211439 is a prime.
It is a super-3 number, since 3×2010482114713 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201048211571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100524105735 + 100524105736.
It is an arithmetic number, because the mean of its divisors is an integer number (100524105736).
Almost surely, 2201048211471 is an apocalyptic number.
201048211471 is a deficient number, since it is larger than the sum of its proper divisors (1).
201048211471 is an equidigital number, since it uses as much as digits as its factorization.
201048211471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3584, while the sum is 31.
The spelling of 201048211471 in words is "two hundred one billion, forty-eight million, two hundred eleven thousand, four hundred seventy-one".
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