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201100031113 is a prime number
BaseRepresentation
bin1011101101001001111…
…1101111010010001001
3201020002000012001111111
42323102133233102021
511243323101443423
6232214543330321
720346306026542
oct2732237572211
9636060161444
10201100031113
11783167a7923
1232b83bb09a1
1315c6b1b1067
149a3a22b4c9
15536ed1460d
hex2ed27ef489

201100031113 has 2 divisors, whose sum is σ = 201100031114. Its totient is φ = 201100031112.

The previous prime is 201100031057. The next prime is 201100031141. The reversal of 201100031113 is 311130001102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 195388752784 + 5711278329 = 442028^2 + 75573^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201100031113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201100031093 and 201100031102.

It is not a weakly prime, because it can be changed into another prime (201100031213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100550015556 + 100550015557.

It is an arithmetic number, because the mean of its divisors is an integer number (100550015557).

Almost surely, 2201100031113 is an apocalyptic number.

It is an amenable number.

201100031113 is a deficient number, since it is larger than the sum of its proper divisors (1).

201100031113 is an equidigital number, since it uses as much as digits as its factorization.

201100031113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 201100031113 its reverse (311130001102), we get a palindrome (512230032215).

The spelling of 201100031113 in words is "two hundred one billion, one hundred million, thirty-one thousand, one hundred thirteen".