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201100201311 = 367033400437
BaseRepresentation
bin1011101101001010000…
…0011000110101011111
3201020002000111200222010
42323102200120311133
511243323122420221
6232214551122303
720346310336002
oct2732240306537
9636060450863
10201100201311
1178316903789
1232b84073393
1315c6b240679
149a3a273539
15536ed49c76
hex2ed2818d5f

201100201311 has 4 divisors (see below), whose sum is σ = 268133601752. Its totient is φ = 134066800872.

The previous prime is 201100201307. The next prime is 201100201327. The reversal of 201100201311 is 113102001102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 201100201311 - 22 = 201100201307 is a prime.

It is a super-2 number, since 2×2011002013112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201100201301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33516700216 + ... + 33516700221.

It is an arithmetic number, because the mean of its divisors is an integer number (67033400438).

Almost surely, 2201100201311 is an apocalyptic number.

201100201311 is a deficient number, since it is larger than the sum of its proper divisors (67033400441).

201100201311 is an equidigital number, since it uses as much as digits as its factorization.

201100201311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67033400440.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 201100201311 its reverse (113102001102), we get a palindrome (314202202413).

The spelling of 201100201311 in words is "two hundred one billion, one hundred million, two hundred one thousand, three hundred eleven".

Divisors: 1 3 67033400437 201100201311