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201100202013 = 3449149294879
BaseRepresentation
bin1011101101001010000…
…0011001000000011101
3201020002000111201221010
42323102200121000131
511243323122431023
6232214551125433
720346310341024
oct2732240310035
9636060451833
10201100202013
1178316904267
1232b84073879
1315c6b240a99
149a3a2738bb
15536ed4a093
hex2ed281901d

201100202013 has 8 divisors (see below), whose sum is σ = 268730784000. Its totient is φ = 133768210688.

The previous prime is 201100202011. The next prime is 201100202027. The reversal of 201100202013 is 310202001102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 201100202013 - 21 = 201100202011 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 201100202013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201100202011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74646093 + ... + 74648786.

It is an arithmetic number, because the mean of its divisors is an integer number (33591348000).

Almost surely, 2201100202013 is an apocalyptic number.

It is an amenable number.

201100202013 is a deficient number, since it is larger than the sum of its proper divisors (67630581987).

201100202013 is a wasteful number, since it uses less digits than its factorization.

201100202013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 149295331.

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 201100202013 its reverse (310202001102), we get a palindrome (511302203115).

The spelling of 201100202013 in words is "two hundred one billion, one hundred million, two hundred two thousand, thirteen".

Divisors: 1 3 449 1347 149294879 447884637 67033400671 201100202013