Base | Representation |
---|---|
bin | 11101010000111001001… |
… | …000000010101111110111 |
3 | 21010020202021010110102121 |
4 | 131100321020002233313 |
5 | 230422013243313442 |
6 | 4135501515420411 |
7 | 265201350230134 |
oct | 35207110025767 |
9 | 7106667113377 |
10 | 2011003104247 |
11 | 705952909975 |
12 | 2858b4a54707 |
13 | 117838007947 |
14 | 6d493d2b58b |
15 | 3749de81967 |
hex | 1d439202bf7 |
2011003104247 has 2 divisors, whose sum is σ = 2011003104248. Its totient is φ = 2011003104246.
The previous prime is 2011003104181. The next prime is 2011003104269. The reversal of 2011003104247 is 7424013001102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2011003104247 - 219 = 2011002579959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011003114247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005501552123 + 1005501552124.
It is an arithmetic number, because the mean of its divisors is an integer number (1005501552124).
Almost surely, 22011003104247 is an apocalyptic number.
2011003104247 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011003104247 is an equidigital number, since it uses as much as digits as its factorization.
2011003104247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 2011003104247 its reverse (7424013001102), we get a palindrome (9435016105349).
The spelling of 2011003104247 in words is "two trillion, eleven billion, three million, one hundred four thousand, two hundred forty-seven".
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